Why doesn't this code:
a[i] = i++;work?
The subexpression i++ causes a side effect--it modifies i's value--which leads to undefined behavior since i is also referenced elsewhere in the same expression. (Note that although the language in K&R suggests that the behavior of this expression is unspecified, the C Standard makes the stronger statement that it is undefined--see question 11.33.)
References:
K&R1 Sec. 2.12
K&R2 Sec. 2.12
ANSI Sec. 3.3
ISO Sec. 6.3
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This page by Steve Summit // Copyright 1995 // mail feedback